What are the solutions to the equation 2x^3+5x^2-8x-20=0 ?

The solutions to the equation 2x^3+5x^2-8x-20=0 are x=-5/2 ,x=-2,x=2

Find the zeros of 2x^3+5x^2-8x-20=0

The zeros of 2x^3+5x^2-8x-20=0 are x=-5/2 ,x=-2,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{3} + 5 x^{2} - 8 x - 20 = 0

x = - \frac{5}{2}, x = - 2, x = 2

Decimal Notation

x = - 2.5, x = - 2, x = 2

Solution steps

2 x^{3} + 5 x^{2} - 8 x - 20 = 0

Factor

2 x^{3} + 5 x^{2} - 8 x - 20 : (2 x + 5) (x + 2) (x - 2)

(2 x + 5) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 5 = 0 or x + 2 = 0 or x - 2 = 0

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - \frac{5}{2}, x = - 2, x = 2

6 x - 5 x^{2} - x^{3} = 0

(x + 1)^{2} - 3 x (x + 1)^{2} = 0

3 a^{4} + 2 a - 46 = 54

- 2 x^{4} + 9 = 2 x - 1

- 2 x^{4} + 9 = 2 x - 3

What are the solutions to the equation 2x^3+5x^2-8x-20=0 ?
The solutions to the equation 2x^3+5x^2-8x-20=0 are x=-5/2 ,x=-2,x=2
Find the zeros of 2x^3+5x^2-8x-20=0
The zeros of 2x^3+5x^2-8x-20=0 are x=-5/2 ,x=-2,x=2