What are the solutions to the equation x(x+2)^3-15(x+2)^2=0 ?

The solutions to the equation x(x+2)^3-15(x+2)^2=0 are x=-2,x=3,x=-5

Find the zeros of x(x+2)^3-15(x+2)^2=0

The zeros of x(x+2)^3-15(x+2)^2=0 are x=-2,x=3,x=-5

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x (x + 2)^{3} - 15 (x + 2)^{2} = 0

x = - 2, x = 3, x = - 5

Solution steps

x (x + 2)^{3} - 15 (x + 2)^{2} = 0

Factor

x (x + 2)^{3} - 15 (x + 2)^{2} : (x + 2)^{2} (x - 3) (x + 5)

(x + 2)^{2} (x - 3) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 3 = 0 or x + 5 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

Solve

x + 5 = 0 : x = - 5

The solutions are

x = - 2, x = 3, x = - 5

- x^{3} + 3 x^{2} + 5 x - 2 = 0, x

z^{4} + 1 + i = 0

x^{3} + 2 x^{2} + 3 x + 2 = 0

(1 + y^{3})^{2} = 0

2 = x^{3}

What are the solutions to the equation x(x+2)^3-15(x+2)^2=0 ?
The solutions to the equation x(x+2)^3-15(x+2)^2=0 are x=-2,x=3,x=-5
Find the zeros of x(x+2)^3-15(x+2)^2=0
The zeros of x(x+2)^3-15(x+2)^2=0 are x=-2,x=3,x=-5