What are the solutions to the equation x^3-6x^2-3x+18=0 ?

The solutions to the equation x^3-6x^2-3x+18=0 are x=6,x=-sqrt(3),x=sqrt(3)

Find the zeros of x^3-6x^2-3x+18=0

The zeros of x^3-6x^2-3x+18=0 are x=6,x=-sqrt(3),x=sqrt(3)

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x^{3} - 6 x^{2} - 3 x + 18 = 0

x = 6, x = - 3, x = 3

Decimal Notation

x = 6, x = - 1.73205 \dots, x = 1.73205 \dots

Solution steps

x^{3} - 6 x^{2} - 3 x + 18 = 0

Factor

x^{3} - 6 x^{2} - 3 x + 18 : (x - 6) (x + 3) (x - 3)

(x - 6) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x - 6 = 0 : x = 6

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 6, x = - 3, x = 3

u^{3} = 8

(x - 3) (x - 3) (x - 4) (x - 5) = 105

2 x^{3} + 3 = 0

x^{4} - 3 x^{3} - 6 x^{2} - 28 x - 24 = 0

(x - 10) (x^{2} + 64) = 0

What are the solutions to the equation x^3-6x^2-3x+18=0 ?
The solutions to the equation x^3-6x^2-3x+18=0 are x=6,x=-sqrt(3),x=sqrt(3)
Find the zeros of x^3-6x^2-3x+18=0
The zeros of x^3-6x^2-3x+18=0 are x=6,x=-sqrt(3),x=sqrt(3)