What are the solutions to the equation x^2-6x=17 ?

The solutions to the equation x^2-6x=17 are x=3+sqrt(26),x=3-sqrt(26)

Find the zeros of x^2-6x=17

The zeros of x^2-6x=17 are x=3+sqrt(26),x=3-sqrt(26)

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x^{2} - 6 x = 17

x = 3 + 26, x = 3 - 26

Decimal Notation

x = 8.09901 \dots, x = - 2.09901 \dots

Solution steps

x^{2} - 6 x = 17

Move

17

to the left side

x^{2} - 6 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 17) = 226

x_{1, 2} = \frac{- ( - 6 ) \pm 2 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 26}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 26}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 26}{2 \cdot 1} : 3 + 26

x = \frac{- ( - 6 ) - 2 26}{2 \cdot 1} : 3 - 26

The solutions to the quadratic equation are:

x = 3 + 26, x = 3 - 26

6 > x - 4

\frac{1}{5} \cdot 75

(52 - e) (32 + e) = f 2 - 6

\frac{x}{6} \geq 5

2 x^{2} - 7 x - 72

What are the solutions to the equation x^2-6x=17 ?
The solutions to the equation x^2-6x=17 are x=3+sqrt(26),x=3-sqrt(26)
Find the zeros of x^2-6x=17
The zeros of x^2-6x=17 are x=3+sqrt(26),x=3-sqrt(26)