What are the solutions to the equation 3x^3-54x^2+240x=0 ?

The solutions to the equation 3x^3-54x^2+240x=0 are x=0,x=8,x=10

Find the zeros of 3x^3-54x^2+240x=0

The zeros of 3x^3-54x^2+240x=0 are x=0,x=8,x=10

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3 x^{3} - 54 x^{2} + 240 x = 0

x = 0, x = 8, x = 10

Solution steps

3 x^{3} - 54 x^{2} + 240 x = 0

Factor

3 x^{3} - 54 x^{2} + 240 x : 3 x (x - 8) (x - 10)

3 x (x - 8) (x - 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 8 = 0 or x - 10 = 0

Solve

x - 8 = 0 : x = 8

Solve

x - 10 = 0 : x = 10

The solutions are

x = 0, x = 8, x = 10

x, 3 x^{2} = λ (4 x^{3})

x^{4} = 4 x^{2} + 5

4 x^{3} - 3 x^{2} + 4 x - 3 = 0

x^{4} - 8 x^{2} - 48 = 0

2 x^{3} + 6 = 0

What are the solutions to the equation 3x^3-54x^2+240x=0 ?
The solutions to the equation 3x^3-54x^2+240x=0 are x=0,x=8,x=10
Find the zeros of 3x^3-54x^2+240x=0
The zeros of 3x^3-54x^2+240x=0 are x=0,x=8,x=10