What are the solutions to the equation 27-x^3=0 ?

The solutions to the equation 27-x^3=0 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i

Find the zeros of 27-x^3=0

The zeros of 27-x^3=0 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i

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27 - x^{3} = 0

x = 3, x = - \frac{3}{2} + \frac{3 3}{2} i, x = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

27 - x^{3} = 0

Move

27

to the right side

- x^{3} = - 27

Divide both sides by

- 1

x^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

x = 3, x = - \frac{3}{2} + \frac{3 3}{2} i, x = - \frac{3}{2} - \frac{3 3}{2} i

400 = \frac{4}{3} π r^{3}

3 x^{4} + x^{2} - 4 = 0

x^{3} = 3 x + 2

2 x (x + 10) (x^{2} + 49) = 0

- a^{3} + 3 a + 2 = 0

What are the solutions to the equation 27-x^3=0 ?
The solutions to the equation 27-x^3=0 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i
Find the zeros of 27-x^3=0
The zeros of 27-x^3=0 are x=3,x=-3/2+(3sqrt(3))/2 i,x=-3/2-(3sqrt(3))/2 i