What are the solutions to the equation (3x^2)5=3(2x^5) ?

The solutions to the equation (3x^2)5=3(2x^5) are

Find the zeros of (3x^2)5=3(2x^5)

The zeros of (3x^2)5=3(2x^5) are

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(3 x^{2}) 5 = 3 (2 x^{5})

Solution steps

(3 x^{2}) \cdot 5 = 3 (2 x^{5})

Move

3 (2 x^{5})

to the left side

3 x^{2} \cdot 5 - 3 \cdot 2 x^{5} = 0

Factor

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

The solutions are

2 x^{3} - 16 = 0

2 + x^{3} - 2 x^{2} = 4 x - 6

5 x^{5} - 30 x^{4} + 45 x^{3} = 0

75 y^{3} + 100 y^{2} - 3 y - 4 = 0

36 x^{3} + 24 x^{2} + 4 x = 0

What are the solutions to the equation (3x^2)5=3(2x^5) ?
The solutions to the equation (3x^2)5=3(2x^5) are
Find the zeros of (3x^2)5=3(2x^5)
The zeros of (3x^2)5=3(2x^5) are