What are the solutions to the equation (1+x)^{10}=2 ?

The solutions to the equation (1+x)^{10}=2 are x=\sqrt[10]{2}-1,x=-\sqrt[10]{2}-1

Find the zeros of (1+x)^{10}=2

The zeros of (1+x)^{10}=2 are x=\sqrt[10]{2}-1,x=-\sqrt[10]{2}-1

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(1 + x)^{10} = 2

Decimal Notation

x = 0.07177 \dots, x = - 2.07177 \dots

Solution steps

(1 + x)^{10} = 2

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

- 2 x^{6} - 2 x^{5} + 2 x^{4} + 2 x^{3} = 0

15 x^{3} + 14 x^{2} - 8 x = 90

x^{3} + 9 x^{2} + 26 x + 24 = 0

x^{4} = i

9 x^{4} = 324 x^{2}

What are the solutions to the equation (1+x)^{10}=2 ?
The solutions to the equation (1+x)^{10}=2 are x=\sqrt[10]{2}-1,x=-\sqrt[10]{2}-1
Find the zeros of (1+x)^{10}=2
The zeros of (1+x)^{10}=2 are x=\sqrt[10]{2}-1,x=-\sqrt[10]{2}-1