What are the solutions to the equation 2x^3-3x^2-4x+6=0 ?

The solutions to the equation 2x^3-3x^2-4x+6=0 are x= 3/2 ,x=-sqrt(2),x=sqrt(2)

Find the zeros of 2x^3-3x^2-4x+6=0

The zeros of 2x^3-3x^2-4x+6=0 are x= 3/2 ,x=-sqrt(2),x=sqrt(2)

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2 x^{3} - 3 x^{2} - 4 x + 6 = 0

x = \frac{3}{2}, x = - 2, x = 2

Decimal Notation

x = 1.5, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

2 x^{3} - 3 x^{2} - 4 x + 6 = 0

Factor

2 x^{3} - 3 x^{2} - 4 x + 6 : (2 x - 3) (x + 2) (x - 2)

(2 x - 3) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0 or x + 2 = 0 or x - 2 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = \frac{3}{2}, x = - 2, x = 2

z^{6} - 28 z^{3} + 27 = 0

- 5 + n^{3} = - 8

12 x^{5} = 2

x^{4} - x^{3} - 4 x^{2} + 2 x + 4 = 0

x^{3} - 2 x^{2} - 16 x + 32 = 0

What are the solutions to the equation 2x^3-3x^2-4x+6=0 ?
The solutions to the equation 2x^3-3x^2-4x+6=0 are x= 3/2 ,x=-sqrt(2),x=sqrt(2)
Find the zeros of 2x^3-3x^2-4x+6=0
The zeros of 2x^3-3x^2-4x+6=0 are x= 3/2 ,x=-sqrt(2),x=sqrt(2)