What are the solutions to the equation x^4+7x^3-2x^2-7x+1=0 ?

The solutions to the equation x^4+7x^3-2x^2-7x+1=0 are x=-1,x=1,x=(-7+sqrt(53))/2 ,x=(-7-sqrt(53))/2

Find the zeros of x^4+7x^3-2x^2-7x+1=0

The zeros of x^4+7x^3-2x^2-7x+1=0 are x=-1,x=1,x=(-7+sqrt(53))/2 ,x=(-7-sqrt(53))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{4} + 7 x^{3} - 2 x^{2} - 7 x + 1 = 0

x = - 1, x = 1, x = \frac{- 7 + 53}{2}, x = \frac{- 7 - 53}{2}

Decimal Notation

x = - 1, x = 1, x = 0.14005 \dots, x = - 7.14005 \dots

Solution steps

x^{4} + 7 x^{3} - 2 x^{2} - 7 x + 1 = 0

Factor

x^{4} + 7 x^{3} - 2 x^{2} - 7 x + 1 : (x + 1) (x - 1) (x^{2} + 7 x - 1)

(x + 1) (x - 1) (x^{2} + 7 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0 or x^{2} + 7 x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

x^{2} + 7 x - 1 = 0 : x = \frac{- 7 + 53}{2}, x = \frac{- 7 - 53}{2}

The solutions are

x = - 1, x = 1, x = \frac{- 7 + 53}{2}, x = \frac{- 7 - 53}{2}

4 x^{2} - 3 x - x^{3} = 0

x^{3} + 7 x^{2} + 9 x + 63 = 0

(x^{3} - 8) = 0

3 x^{4} + 2 x^{2} = 1

x, (x + y)^{5} = 3

What are the solutions to the equation x^4+7x^3-2x^2-7x+1=0 ?
The solutions to the equation x^4+7x^3-2x^2-7x+1=0 are x=-1,x=1,x=(-7+sqrt(53))/2 ,x=(-7-sqrt(53))/2
Find the zeros of x^4+7x^3-2x^2-7x+1=0
The zeros of x^4+7x^3-2x^2-7x+1=0 are x=-1,x=1,x=(-7+sqrt(53))/2 ,x=(-7-sqrt(53))/2