What are the solutions to the equation (x+4)(x-6)(4-5)=0 ?

The solutions to the equation (x+4)(x-6)(4-5)=0 are x=-4,x=6

Find the zeros of (x+4)(x-6)(4-5)=0

The zeros of (x+4)(x-6)(4-5)=0 are x=-4,x=6

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(x + 4) (x - 6) (4 - 5) = 0

x = - 4, x = 6

Solution steps

(x + 4) (x - 6) (4 - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x - 6 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 6 = 0 : x = 6

The solutions to the quadratic equation are:

x = - 4, x = 6

9 (x - 5) = 8 (x + 5)

7 x^{2} - 2 x + 3 = 0

\frac{- 3 - 2}{3 17}

6 x^{2} + 21 x - 12

\frac{x ^{- 2} - y ^{- 2}}{x ^{- 1} + y ^{- 1}}

What are the solutions to the equation (x+4)(x-6)(4-5)=0 ?
The solutions to the equation (x+4)(x-6)(4-5)=0 are x=-4,x=6
Find the zeros of (x+4)(x-6)(4-5)=0
The zeros of (x+4)(x-6)(4-5)=0 are x=-4,x=6