What are the solutions to the equation x^3-9x^2-x+9=0 ?

The solutions to the equation x^3-9x^2-x+9=0 are x=9,x=-1,x=1

Find the zeros of x^3-9x^2-x+9=0

The zeros of x^3-9x^2-x+9=0 are x=9,x=-1,x=1

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x^{3} - 9 x^{2} - x + 9 = 0

x = 9, x = - 1, x = 1

Solution steps

x^{3} - 9 x^{2} - x + 9 = 0

Factor

x^{3} - 9 x^{2} - x + 9 : (x - 9) (x + 1) (x - 1)

(x - 9) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 9 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x - 9 = 0 : x = 9

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 9, x = - 1, x = 1

x^{10} - 1 = 0

y^{4} - 20 y^{2} + 64 = 0

x^{4} + 9 = 0

3 (2 x + 8 - 2) x^{2} = 9

(x - 1) (x^{2} - 11 x + 30) = 0

What are the solutions to the equation x^3-9x^2-x+9=0 ?
The solutions to the equation x^3-9x^2-x+9=0 are x=9,x=-1,x=1
Find the zeros of x^3-9x^2-x+9=0
The zeros of x^3-9x^2-x+9=0 are x=9,x=-1,x=1