What are the solutions to the equation 2x(3x^2+1)=0 ?

The solutions to the equation 2x(3x^2+1)=0 are x=0,x= 1/(sqrt(3))i,x=-1/(sqrt(3))i

Find the zeros of 2x(3x^2+1)=0

The zeros of 2x(3x^2+1)=0 are x=0,x= 1/(sqrt(3))i,x=-1/(sqrt(3))i

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2 x (3 x^{2} + 1) = 0

x = 0, x = \frac{1}{3} i, x = - \frac{1}{3} i

Solution steps

2 x (3 x^{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x^{2} + 1 = 0

Solve

3 x^{2} + 1 = 0 : x = \frac{1}{3} i, x = - \frac{1}{3} i

The solutions are

x = 0, x = \frac{1}{3} i, x = - \frac{1}{3} i

x^{3} - 2 x^{2} + 3 x - 1 = 0

28 x^{3} + 88 x^{2} - 37 x - 7 = 0

2 x^{3} - 3 x^{2} + 4 x - 5 = 0

81 (x - 2)^{4} - 3 (x - 2) = 0

x^{6} = - 2^{6}

What are the solutions to the equation 2x(3x^2+1)=0 ?
The solutions to the equation 2x(3x^2+1)=0 are x=0,x= 1/(sqrt(3))i,x=-1/(sqrt(3))i
Find the zeros of 2x(3x^2+1)=0
The zeros of 2x(3x^2+1)=0 are x=0,x= 1/(sqrt(3))i,x=-1/(sqrt(3))i