What are the solutions to the equation 3(5x+2)(x^2-81)=0 ?

The solutions to the equation 3(5x+2)(x^2-81)=0 are x=-9,x=9,x=-2/5

Find the zeros of 3(5x+2)(x^2-81)=0

The zeros of 3(5x+2)(x^2-81)=0 are x=-9,x=9,x=-2/5

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3 (5 x + 2) (x^{2} - 81) = 0

x = - 9, x = 9, x = - \frac{2}{5}

Decimal Notation

x = - 9, x = 9, x = - 0.4

Solution steps

3 (5 x + 2) (x^{2} - 81) = 0

Factor

3 (5 x + 2) (x^{2} - 81) : 3 (x + 9) (x - 9) (5 x + 2)

3 (x + 9) (x - 9) (5 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 9 = 0 or x - 9 = 0 or 5 x + 2 = 0

Solve

x + 9 = 0 : x = - 9

Solve

x - 9 = 0 : x = 9

Solve

5 x + 2 = 0 : x = - \frac{2}{5}

The solutions are

x = - 9, x = 9, x = - \frac{2}{5}

2 x^{3} - 16 x^{2} - 18 x = 0

27 x^{3} = (x + 5)^{3}

(x - 10) (x - 3) (x + 5) = 0

8 x^{3} - 12 x^{2} + 2 x - 3 = 0

(x - 2)^{3} - 5 = 0

What are the solutions to the equation 3(5x+2)(x^2-81)=0 ?
The solutions to the equation 3(5x+2)(x^2-81)=0 are x=-9,x=9,x=-2/5
Find the zeros of 3(5x+2)(x^2-81)=0
The zeros of 3(5x+2)(x^2-81)=0 are x=-9,x=9,x=-2/5