What are the solutions to the equation 2x^3-19x^2+8x+9=0 ?

The solutions to the equation 2x^3-19x^2+8x+9=0 are x=1,x=-1/2 ,x=9

Find the zeros of 2x^3-19x^2+8x+9=0

The zeros of 2x^3-19x^2+8x+9=0 are x=1,x=-1/2 ,x=9

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2 x^{3} - 19 x^{2} + 8 x + 9 = 0

x = 1, x = - \frac{1}{2}, x = 9

Decimal Notation

x = 1, x = - 0.5, x = 9

Solution steps

2 x^{3} - 19 x^{2} + 8 x + 9 = 0

Factor

2 x^{3} - 19 x^{2} + 8 x + 9 : (x - 1) (2 x + 1) (x - 9)

(x - 1) (2 x + 1) (x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x + 1 = 0 or x - 9 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x - 9 = 0 : x = 9

The solutions are

x = 1, x = - \frac{1}{2}, x = 9

y^{3} - 49 y = 0

x^{4} + 8 x^{2} - 48 = 0

3 y^{3} - 14 y^{2} - 5 y = 0

n^{3} = 0.008

- 15 x^{1} + 6 x^{2} - 10 x^{3} = - 12

What are the solutions to the equation 2x^3-19x^2+8x+9=0 ?
The solutions to the equation 2x^3-19x^2+8x+9=0 are x=1,x=-1/2 ,x=9
Find the zeros of 2x^3-19x^2+8x+9=0
The zeros of 2x^3-19x^2+8x+9=0 are x=1,x=-1/2 ,x=9