What are the solutions to the equation 75=-5+10b^3 ?

The solutions to the equation 75=-5+10b^3 are b=2,b=-1+sqrt(3)i,b=-1-sqrt(3)i

Find the zeros of 75=-5+10b^3

The zeros of 75=-5+10b^3 are b=2,b=-1+sqrt(3)i,b=-1-sqrt(3)i

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75 = - 5 + 10 b^{3}

b = 2, b = - 1 + 3 i, b = - 1 - 3 i

Solution steps

75 = - 5 + 10 b^{3}

Switch sides

- 5 + 10 b^{3} = 75

Move

5

to the right side

10 b^{3} = 80

Divide both sides by

10

b^{3} = 8

For

x^{3} = f (a)

the solutions are

Simplify

b = 2, b = - 1 + 3 i, b = - 1 - 3 i

15 x^{4} + 7 x^{2} = 2

14 x^{2} - 24 x - 2 x^{3} = 0

x^{4} - 49 x^{2} = 0

\frac{x ^{3}}{7} = 27

(1 - λ) (- λ) (2 - λ) + λ = 0

What are the solutions to the equation 75=-5+10b^3 ?
The solutions to the equation 75=-5+10b^3 are b=2,b=-1+sqrt(3)i,b=-1-sqrt(3)i
Find the zeros of 75=-5+10b^3
The zeros of 75=-5+10b^3 are b=2,b=-1+sqrt(3)i,b=-1-sqrt(3)i