What are the solutions to the equation pir^2=2305 ?

The solutions to the equation pir^2=2305 are r=sqrt((2305)/pi),r=-sqrt((2305)/pi)

Find the zeros of pir^2=2305

The zeros of pir^2=2305 are r=sqrt((2305)/pi),r=-sqrt((2305)/pi)

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π r^{2} = 2305

r = \frac{2305}{π}, r = - \frac{2305}{π}

Decimal Notation

r = 27.08697 \dots, r = - 27.08697 \dots

Solution steps

π r^{2} = 2305

Divide both sides by

π

r^{2} = \frac{2305}{π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{2305}{π}, r = - \frac{2305}{π}

(x - y) (x - y)

3 x - 8 \geq - 14

(\frac{2 a ^{- 1} b}{a ^{2} b ^{- 3}})^{- 2}

- \frac{2}{3}

0.5 a c + 0.5 c b

What are the solutions to the equation pir^2=2305 ?
The solutions to the equation pir^2=2305 are r=sqrt((2305)/pi),r=-sqrt((2305)/pi)
Find the zeros of pir^2=2305
The zeros of pir^2=2305 are r=sqrt((2305)/pi),r=-sqrt((2305)/pi)