What are the solutions to the equation (u^2-5u-6)(5u+25)=0 ?

The solutions to the equation (u^2-5u-6)(5u+25)=0 are u=-1,u=6,u=-5

Find the zeros of (u^2-5u-6)(5u+25)=0

The zeros of (u^2-5u-6)(5u+25)=0 are u=-1,u=6,u=-5

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(u^{2} - 5 u - 6) (5 u + 25) = 0

u = - 1, u = 6, u = - 5

Solution steps

(u^{2} - 5 u - 6) (5 u + 25) = 0

Factor

(u^{2} - 5 u - 6) (5 u + 25) : 5 (u + 1) (u - 6) (u + 5)

5 (u + 1) (u - 6) (u + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

u + 1 = 0 or u - 6 = 0 or u + 5 = 0

Solve

u + 1 = 0 : u = - 1

Solve

u - 6 = 0 : u = 6

Solve

u + 5 = 0 : u = - 5

The solutions are

u = - 1, u = 6, u = - 5

x^{6} - 2 x^{4} = 0

10 = 500 x^{3}

x^{6} + 3 x^{3} + 2 = 0

3 x^{3} - 5 x^{2} - 4 x - 24 = 0

- 4 x^{5} + 6 x^{4} + 4 x^{3} - 6 x^{2} = 0

What are the solutions to the equation (u^2-5u-6)(5u+25)=0 ?
The solutions to the equation (u^2-5u-6)(5u+25)=0 are u=-1,u=6,u=-5
Find the zeros of (u^2-5u-6)(5u+25)=0
The zeros of (u^2-5u-6)(5u+25)=0 are u=-1,u=6,u=-5