What are the solutions to the equation 0=4x^3-8x ?

The solutions to the equation 0=4x^3-8x are x=0,x=-sqrt(2),x=sqrt(2)

Find the zeros of 0=4x^3-8x

The zeros of 0=4x^3-8x are x=0,x=-sqrt(2),x=sqrt(2)

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0 = 4 x^{3} - 8 x

x = 0, x = - 2, x = 2

Decimal Notation

x = 0, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

0 = 4 x^{3} - 8 x

Switch sides

4 x^{3} - 8 x = 0

Factor

4 x^{3} - 8 x : 4 x (x + 2) (x - 2)

4 x (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = - 2, x = 2

z^{6} = - 9

y^{6} - 9 y^{3} + 8 = 0

3 x^{3} - 1 9^{2} + 36 x - 10 = 0

4 x^{4} = 256 x

(3 x + 7) (x^{2} - 100) = 0

What are the solutions to the equation 0=4x^3-8x ?
The solutions to the equation 0=4x^3-8x are x=0,x=-sqrt(2),x=sqrt(2)
Find the zeros of 0=4x^3-8x
The zeros of 0=4x^3-8x are x=0,x=-sqrt(2),x=sqrt(2)