What are the solutions to the equation 2x^4=-128x ?

The solutions to the equation 2x^4=-128x are x=0,x=-4,x=2+2sqrt(3)i,x=2-2sqrt(3)i

Find the zeros of 2x^4=-128x

The zeros of 2x^4=-128x are x=0,x=-4,x=2+2sqrt(3)i,x=2-2sqrt(3)i

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2 x^{4} = - 128 x

x = 0, x = - 4, x = 2 + 23 i, x = 2 - 23 i

Solution steps

2 x^{4} = - 128 x

Move

128 x

to the left side

2 x^{4} + 128 x = 0

Factor

2 x^{4} + 128 x : 2 x (x + 4) (x^{2} - 4 x + 16)

2 x (x + 4) (x^{2} - 4 x + 16) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 4 = 0 or x^{2} - 4 x + 16 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x^{2} - 4 x + 16 = 0 : x = 2 + 23 i, x = 2 - 23 i

The solutions are

x = 0, x = - 4, x = 2 + 23 i, x = 2 - 23 i

x^{9} \cdot 300 = 2400

x^{3} - 7 x^{2} - 9 x + 63 = 0

x^{4} - 14 x^{2} - 32 = 0

y^{4} = 289

(t^{2} - 82)^{2} = 324

What are the solutions to the equation 2x^4=-128x ?
The solutions to the equation 2x^4=-128x are x=0,x=-4,x=2+2sqrt(3)i,x=2-2sqrt(3)i
Find the zeros of 2x^4=-128x
The zeros of 2x^4=-128x are x=0,x=-4,x=2+2sqrt(3)i,x=2-2sqrt(3)i