What are the solutions to the equation -34=3x^4+118 ?

The solutions to the equation -34=3x^4+118 are

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-34=3x^4+118

- 34 = 3 x^{4} + 118

x = 4 \frac{38}{3} + \frac{38}{3 4 \frac{38}{3}} i, x = - 4 \frac{38}{3} - \frac{38}{3 4 \frac{38}{3}} i, x = 4 \frac{38}{3} - \frac{38}{3 4 \frac{38}{3}} i, x = - 4 \frac{38}{3} + \frac{38}{3 4 \frac{38}{3}} i

Solution steps

- 34 = 3 x^{4} + 118

Switch sides

3 x^{4} + 118 = - 34

Move

118

to the right side

3 x^{4} = - 152

Divide both sides by

3

x^{4} = - \frac{152}{3}

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} = - \frac{152}{3}

Solve

u^{2} = - \frac{152}{3} : u = \frac{2 38}{3} i, u = - \frac{2 38}{3} i

u = \frac{2 38}{3} i, u = - \frac{2 38}{3} i

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{2 38}{3} i : x = 4 \frac{38}{3} + \frac{38}{3 4 \frac{38}{3}} i, x = - 4 \frac{38}{3} - \frac{38}{3 4 \frac{38}{3}} i

Solve

x^{2} = - \frac{2 38}{3} i : x = 4 \frac{38}{3} - \frac{38}{3 4 \frac{38}{3}} i, x = - 4 \frac{38}{3} + \frac{38}{3 4 \frac{38}{3}} i

The solutions are

x = 4 \frac{38}{3} + \frac{38}{3 4 \frac{38}{3}} i, x = - 4 \frac{38}{3} - \frac{38}{3 4 \frac{38}{3}} i, x = 4 \frac{38}{3} - \frac{38}{3 4 \frac{38}{3}} i, x = - 4 \frac{38}{3} + \frac{38}{3 4 \frac{38}{3}} i

x^{7} - 7 x^{6} = 0

12 x^{4} - 7 x^{2} - 6 x + 16 x^{3} = 0

19 = 32 (1 - b)^{26}

x^{3} + x = - 2

x^{3} + x = 10

What are the solutions to the equation -34=3x^4+118 ?
The solutions to the equation -34=3x^4+118 are
Find the zeros of -34=3x^4+118
The zeros of -34=3x^4+118 are