What are the solutions to the equation -x^3+3x^2+6x-8=0 ?

The solutions to the equation -x^3+3x^2+6x-8=0 are x=1,x=-2,x=4

Find the zeros of -x^3+3x^2+6x-8=0

The zeros of -x^3+3x^2+6x-8=0 are x=1,x=-2,x=4

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- x^{3} + 3 x^{2} + 6 x - 8 = 0

x = 1, x = - 2, x = 4

Solution steps

- x^{3} + 3 x^{2} + 6 x - 8 = 0

Factor

- x^{3} + 3 x^{2} + 6 x - 8 : - (x - 1) (x + 2) (x - 4)

- (x - 1) (x + 2) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0 or x - 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 4 = 0 : x = 4

The solutions are

x = 1, x = - 2, x = 4

x^{3} - 8 x = 0

x^{3} = x + 2

x^{3} - 13 x^{2} + 42 x = 0

x^{6} + x^{3} - 6 = 0

2 x^{3} - x^{2} + 2 x - 1 = 0

What are the solutions to the equation -x^3+3x^2+6x-8=0 ?
The solutions to the equation -x^3+3x^2+6x-8=0 are x=1,x=-2,x=4
Find the zeros of -x^3+3x^2+6x-8=0
The zeros of -x^3+3x^2+6x-8=0 are x=1,x=-2,x=4