What are the solutions to the equation (2x-x^2)^5=0 ?

The solutions to the equation (2x-x^2)^5=0 are x=0,x=2

Find the zeros of (2x-x^2)^5=0

The zeros of (2x-x^2)^5=0 are x=0,x=2

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(2 x - x^{2})^{5} = 0

x = 0, x = 2

Solution steps

(2 x - x^{2})^{5} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

2 x - x^{2} = 0 : x = 0, x = 2

The solutions are

x = 0, x = 2

4 x^{6} - 19 x^{4} + 11 x^{2} + 4 = 0

x (x + 1) (x + 2) = 9240

b^{4} = 16

x^{6} - 4 x^{3} + c = 0

3 x^{3} = 12 x

What are the solutions to the equation (2x-x^2)^5=0 ?
The solutions to the equation (2x-x^2)^5=0 are x=0,x=2
Find the zeros of (2x-x^2)^5=0
The zeros of (2x-x^2)^5=0 are x=0,x=2