What are the solutions to the equation 4x^9-4x=0 ?

The solutions to the equation 4x^9-4x=0 are

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4x^9-4x=0

4 x^{9} - 4 x = 0

x = 0, x = - \frac{2}{2} + i \frac{2}{2}, x = - \frac{2}{2} - i \frac{2}{2}, x = \frac{2}{2} + i \frac{2}{2}, x = \frac{2}{2} - i \frac{2}{2}, x = i, x = - i, x = - 1, x = 1

Solution steps

4 x^{9} - 4 x = 0

Factor

4 x^{9} - 4 x : 4 x (x^{2} + 2 x + 1) (x^{2} - 2 x + 1) (x^{2} + 1) (x + 1) (x - 1)

4 x (x^{2} + 2 x + 1) (x^{2} - 2 x + 1) (x^{2} + 1) (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 2 x + 1 = 0 or x^{2} - 2 x + 1 = 0 or x^{2} + 1 = 0 or x + 1 = 0 or x - 1 = 0

Solve

x^{2} + 2 x + 1 = 0 : x = - \frac{2}{2} + i \frac{2}{2}, x = - \frac{2}{2} - i \frac{2}{2}

Solve

x^{2} - 2 x + 1 = 0 : x = \frac{2}{2} + i \frac{2}{2}, x = \frac{2}{2} - i \frac{2}{2}

Solve

x^{2} + 1 = 0 : x = i, x = - i

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = - \frac{2}{2} + i \frac{2}{2}, x = - \frac{2}{2} - i \frac{2}{2}, x = \frac{2}{2} + i \frac{2}{2}, x = \frac{2}{2} - i \frac{2}{2}, x = i, x = - i, x = - 1, x = 1

4 (x - 6)^{3} (x^{2} + 7) = 0

x, x^{4} + x^{2} - 1 = 0

5 x^{5} - 20 x = 0

x^{3} - 2 x^{2} + 4 x - 2 = 0

5 x^{5} = - 40 x^{2}

What are the solutions to the equation 4x^9-4x=0 ?
The solutions to the equation 4x^9-4x=0 are
Find the zeros of 4x^9-4x=0
The zeros of 4x^9-4x=0 are