What are the solutions to the equation x^3-2x^2-x+7=x^2-3x+7 ?

The solutions to the equation x^3-2x^2-x+7=x^2-3x+7 are x=0,x=1,x=2

Find the zeros of x^3-2x^2-x+7=x^2-3x+7

The zeros of x^3-2x^2-x+7=x^2-3x+7 are x=0,x=1,x=2

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x^{3} - 2 x^{2} - x + 7 = x^{2} - 3 x + 7

x = 0, x = 1, x = 2

Solution steps

x^{3} - 2 x^{2} - x + 7 = x^{2} - 3 x + 7

Move

7

to the right side

x^{3} - 2 x^{2} - x = x^{2} - 3 x

Move

3 x

to the left side

x^{3} - 2 x^{2} + 2 x = x^{2}

Move

x^{2}

to the left side

x^{3} - 3 x^{2} + 2 x = 0

Factor

x^{3} - 3 x^{2} + 2 x : x (x - 1) (x - 2)

x (x - 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 1, x = 2

a^{3} - 3 a - 2 = 0

2 x^{3} - 3 x = 0

x^{3} - 20 = 7

x^{2} (x - 7) = 0

4 x^{3} + 3 x^{2} + 2 x + 1 = 0

What are the solutions to the equation x^3-2x^2-x+7=x^2-3x+7 ?
The solutions to the equation x^3-2x^2-x+7=x^2-3x+7 are x=0,x=1,x=2
Find the zeros of x^3-2x^2-x+7=x^2-3x+7
The zeros of x^3-2x^2-x+7=x^2-3x+7 are x=0,x=1,x=2