What are the solutions to the equation x^3-4x^2-2x+3=0 ?

The solutions to the equation x^3-4x^2-2x+3=0 are x=-1,x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2

Find the zeros of x^3-4x^2-2x+3=0

The zeros of x^3-4x^2-2x+3=0 are x=-1,x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2

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x^{3} - 4 x^{2} - 2 x + 3 = 0

x = - 1, x = \frac{5 + 13}{2}, x = \frac{5 - 13}{2}

Decimal Notation

x = - 1, x = 4.30277 \dots, x = 0.69722 \dots

Solution steps

x^{3} - 4 x^{2} - 2 x + 3 = 0

Factor

x^{3} - 4 x^{2} - 2 x + 3 : (x + 1) (x^{2} - 5 x + 3)

(x + 1) (x^{2} - 5 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} - 5 x + 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} - 5 x + 3 = 0 : x = \frac{5 + 13}{2}, x = \frac{5 - 13}{2}

The solutions are

x = - 1, x = \frac{5 + 13}{2}, x = \frac{5 - 13}{2}

x^{3} - 6 x^{2} + 9 x + 2 = 0

(- x - 2) (x^{2} + 4 x + 3) = 0

2 x^{3} - x = 0

z^{3} + 4 z^{2} + 6 z + 4 = 0

- a^{3} + 6 a^{2} + 135 a + 400 = 0

What are the solutions to the equation x^3-4x^2-2x+3=0 ?
The solutions to the equation x^3-4x^2-2x+3=0 are x=-1,x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2
Find the zeros of x^3-4x^2-2x+3=0
The zeros of x^3-4x^2-2x+3=0 are x=-1,x=(5+sqrt(13))/2 ,x=(5-sqrt(13))/2