What are the solutions to the equation x^3+7x^2-3x=21 ?

The solutions to the equation x^3+7x^2-3x=21 are x=-7,x=-sqrt(3),x=sqrt(3)

Find the zeros of x^3+7x^2-3x=21

The zeros of x^3+7x^2-3x=21 are x=-7,x=-sqrt(3),x=sqrt(3)

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x^{3} + 7 x^{2} - 3 x = 21

x = - 7, x = - 3, x = 3

Decimal Notation

x = - 7, x = - 1.73205 \dots, x = 1.73205 \dots

Solution steps

x^{3} + 7 x^{2} - 3 x = 21

Move

21

to the left side

x^{3} + 7 x^{2} - 3 x - 21 = 0

Factor

x^{3} + 7 x^{2} - 3 x - 21 : (x + 7) (x + 3) (x - 3)

(x + 7) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 7 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 7 = 0 : x = - 7

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 7, x = - 3, x = 3

2 m^{3} (4 - 3 m) (5 m + \frac{2}{3}) = 0

5 x^{3} + 7 x^{2} - 20 x - 28 = 0

3 x^{3} - 6 x^{2} = 0

x^{3} - 6 x^{2} - 13 x + 78 = 0

x^{5} x - 6 = 39

What are the solutions to the equation x^3+7x^2-3x=21 ?
The solutions to the equation x^3+7x^2-3x=21 are x=-7,x=-sqrt(3),x=sqrt(3)
Find the zeros of x^3+7x^2-3x=21
The zeros of x^3+7x^2-3x=21 are x=-7,x=-sqrt(3),x=sqrt(3)