What are the solutions to the equation 1.035=(1+r/4)^4 ?

The solutions to the equation 1.035=(1+r/4)^4 are r=0.03454…,r=-8.03454…

Find the zeros of 1.035=(1+r/4)^4

The zeros of 1.035=(1+r/4)^4 are r=0.03454…,r=-8.03454…

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1.035 = (1 + \frac{r}{4})^{4}

r = 0.03454 \dots, r = - 8.03454 \dots

Solution steps

1.035 = (1 + \frac{r}{4})^{4}

Switch sides

(1 + \frac{r}{4})^{4} = 1.035

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

r = 0.03454 \dots, r = - 8.03454 \dots

- x^{3} - x + 2 = 0

x^{4} - 3 x^{3} + 3 x^{2} + 1 = 0

2 x^{4} - 12 x^{2} + 16 = 0

- 40 + 6 x^{3} = 0

3 x^{4} + 5 x^{3} + 3 x^{2} + x = 20

What are the solutions to the equation 1.035=(1+r/4)^4 ?
The solutions to the equation 1.035=(1+r/4)^4 are r=0.03454…,r=-8.03454…
Find the zeros of 1.035=(1+r/4)^4
The zeros of 1.035=(1+r/4)^4 are r=0.03454…,r=-8.03454…