What are the solutions to the equation (4m^2+2)^2=0 ?

The solutions to the equation (4m^2+2)^2=0 are m= 1/(sqrt(2))i,m=-1/(sqrt(2))i

Find the zeros of (4m^2+2)^2=0

The zeros of (4m^2+2)^2=0 are m= 1/(sqrt(2))i,m=-1/(sqrt(2))i

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(4 m^{2} + 2)^{2} = 0

m = \frac{1}{2} i, m = - \frac{1}{2} i

Solution steps

(4 m^{2} + 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

4 m^{2} + 2 = 0 : m = \frac{1}{2} i, m = - \frac{1}{2} i

The solutions are

m = \frac{1}{2} i, m = - \frac{1}{2} i

x^{5} + 1024 = 0

x^{3} + 2 x^{2} - 49 x - 98 = 0

(7.2 + x^{2})^{2} = x^{2} + 2.6 7^{2}

6 x^{4} = 1296 x

2 x^{3} - 9 x^{2} + 12 x - 4 = 0

What are the solutions to the equation (4m^2+2)^2=0 ?
The solutions to the equation (4m^2+2)^2=0 are m= 1/(sqrt(2))i,m=-1/(sqrt(2))i
Find the zeros of (4m^2+2)^2=0
The zeros of (4m^2+2)^2=0 are m= 1/(sqrt(2))i,m=-1/(sqrt(2))i