What are the solutions to the equation x^3(x+1)=-6 ?

The solutions to the equation x^3(x+1)=-6 are No Solution for x\in\mathbb{R}

Find the zeros of x^3(x+1)=-6

The zeros of x^3(x+1)=-6 are No Solution for x\in\mathbb{R}

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x^{3} (x + 1) = - 6

No Solution for x \in R

Solution steps

x^{3} (x + 1) = - 6

Expand

x^{3} (x + 1) : x^{4} + x^{3}

x^{4} + x^{3} = - 6

Move

6

to the left side

x^{4} + x^{3} + 6 = 0

Find one solution for

x^{4} + x^{3} + 6 = 0

using Newton-Raphson:

No Solution for

x \in R

The solution is

No Solution for x \in R

x, - y = x^{3}

(1 + 0.8) = (1 + \frac{x}{12})^{3}

2 x^{3} + x^{2} - 6 x + 7 = 0

x^{3} - x^{2} - 8 = 0

y^{3} + 2 y^{2} = 25 y + 50

What are the solutions to the equation x^3(x+1)=-6 ?
The solutions to the equation x^3(x+1)=-6 are No Solution for x\in\mathbb{R}
Find the zeros of x^3(x+1)=-6
The zeros of x^3(x+1)=-6 are No Solution for x\in\mathbb{R}