What are the solutions to the equation 9^2+10^2=c^2 ?

The solutions to the equation 9^2+10^2=c^2 are c=sqrt(181),c=-sqrt(181)

Find the zeros of 9^2+10^2=c^2

The zeros of 9^2+10^2=c^2 are c=sqrt(181),c=-sqrt(181)

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9^{2} + 1 0^{2} = c^{2}

c = 181, c = - 181

Decimal Notation

c = 13.45362 \dots, c = - 13.45362 \dots

Solution steps

9^{2} + 1 0^{2} = c^{2}

Switch sides

c^{2} = 9^{2} + 1 0^{2}

Simplify

9^{2} + 1 0^{2} : 181

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 181, c = - 181

\frac{14}{5 + 4 x} \leq 7

\frac{r}{10} + 4 = 5

\frac{1}{2} + \frac{1}{3} + \frac{1}{5}

x^{2} - 2 x - 63 < 0

j + 6 < 9

What are the solutions to the equation 9^2+10^2=c^2 ?
The solutions to the equation 9^2+10^2=c^2 are c=sqrt(181),c=-sqrt(181)
Find the zeros of 9^2+10^2=c^2
The zeros of 9^2+10^2=c^2 are c=sqrt(181),c=-sqrt(181)