What are the solutions to the equation 3x^3+19x^2+21x+5=0 ?

The solutions to the equation 3x^3+19x^2+21x+5=0 are x=-1,x=-1/3 ,x=-5

Find the zeros of 3x^3+19x^2+21x+5=0

The zeros of 3x^3+19x^2+21x+5=0 are x=-1,x=-1/3 ,x=-5

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3 x^{3} + 19 x^{2} + 21 x + 5 = 0

x = - 1, x = - \frac{1}{3}, x = - 5

Decimal Notation

x = - 1, x = - 0.33333 \dots, x = - 5

Solution steps

3 x^{3} + 19 x^{2} + 21 x + 5 = 0

Factor

3 x^{3} + 19 x^{2} + 21 x + 5 : (x + 1) (3 x + 1) (x + 5)

(x + 1) (3 x + 1) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 3 x + 1 = 0 or x + 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

x + 5 = 0 : x = - 5

The solutions are

x = - 1, x = - \frac{1}{3}, x = - 5

3 x^{3} + 4 x^{2} - 45 x - 60 = 0

x^{4} + 34 x^{2} + 225 = 0

x^{10} = 1.4567

t^{3} = 4

3 x^{1} - 6 x^{2} + 7 x^{3} = 4

What are the solutions to the equation 3x^3+19x^2+21x+5=0 ?
The solutions to the equation 3x^3+19x^2+21x+5=0 are x=-1,x=-1/3 ,x=-5
Find the zeros of 3x^3+19x^2+21x+5=0
The zeros of 3x^3+19x^2+21x+5=0 are x=-1,x=-1/3 ,x=-5