What are the solutions to the equation 16x^3+96x^2-25x-150=0 ?

The solutions to the equation 16x^3+96x^2-25x-150=0 are x=-6,x=-5/4 ,x= 5/4

Find the zeros of 16x^3+96x^2-25x-150=0

The zeros of 16x^3+96x^2-25x-150=0 are x=-6,x=-5/4 ,x= 5/4

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16 x^{3} + 96 x^{2} - 25 x - 150 = 0

x = - 6, x = - \frac{5}{4}, x = \frac{5}{4}

Decimal Notation

x = - 6, x = - 1.25, x = 1.25

Solution steps

16 x^{3} + 96 x^{2} - 25 x - 150 = 0

Factor

16 x^{3} + 96 x^{2} - 25 x - 150 : (x + 6) (4 x + 5) (4 x - 5)

(x + 6) (4 x + 5) (4 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 6 = 0 or 4 x + 5 = 0 or 4 x - 5 = 0

Solve

x + 6 = 0 : x = - 6

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

Solve

4 x - 5 = 0 : x = \frac{5}{4}

The solutions are

x = - 6, x = - \frac{5}{4}, x = \frac{5}{4}

c x^{2} + 6 x = x^{3} - c x

x^{4} - 2 x^{3} - 2 x - 1 = 0

(x - 3)^{4} + (x - 5)^{4} = 2

z^{4} = 128 + 1283 i

x^{6} - 16 x^{2} = 0

What are the solutions to the equation 16x^3+96x^2-25x-150=0 ?
The solutions to the equation 16x^3+96x^2-25x-150=0 are x=-6,x=-5/4 ,x= 5/4
Find the zeros of 16x^3+96x^2-25x-150=0
The zeros of 16x^3+96x^2-25x-150=0 are x=-6,x=-5/4 ,x= 5/4