What are the solutions to the equation -x^4+x^3+3x^2-x-2=0 ?

The solutions to the equation -x^4+x^3+3x^2-x-2=0 are x=-1,x=2,x=1

Find the zeros of -x^4+x^3+3x^2-x-2=0

The zeros of -x^4+x^3+3x^2-x-2=0 are x=-1,x=2,x=1

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- x^{4} + x^{3} + 3 x^{2} - x - 2 = 0

x = - 1, x = 2, x = 1

Solution steps

- x^{4} + x^{3} + 3 x^{2} - x - 2 = 0

Factor

- x^{4} + x^{3} + 3 x^{2} - x - 2 : - (x + 1)^{2} (x - 2) (x - 1)

- (x + 1)^{2} (x - 2) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 2 = 0 or x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

Solve

x - 1 = 0 : x = 1

The solutions are

x = - 1, x = 2, x = 1

- x^{3} + x^{2} + 4 \cdot x - 4 = 0

y^{4} - 25 y^{2} + 144 = 0

4 y^{3} - 36 y = 0

- 11 = 5 m^{3} - 6

(3 - 15 x)^{3} = - 5

What are the solutions to the equation -x^4+x^3+3x^2-x-2=0 ?
The solutions to the equation -x^4+x^3+3x^2-x-2=0 are x=-1,x=2,x=1
Find the zeros of -x^4+x^3+3x^2-x-2=0
The zeros of -x^4+x^3+3x^2-x-2=0 are x=-1,x=2,x=1