What are the solutions to the equation (15-5c)(5c+5)(-c+6)=0 ?

The solutions to the equation (15-5c)(5c+5)(-c+6)=0 are c=3,c=-1,c=6

Find the zeros of (15-5c)(5c+5)(-c+6)=0

The zeros of (15-5c)(5c+5)(-c+6)=0 are c=3,c=-1,c=6

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(15 - 5 c) (5 c + 5) (- c + 6) = 0

c = 3, c = - 1, c = 6

Solution steps

(15 - 5 c) (5 c + 5) (- c + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

15 - 5 c = 0 or 5 c + 5 = 0 or - c + 6 = 0

Solve

15 - 5 c = 0 : c = 3

Solve

5 c + 5 = 0 : c = - 1

Solve

- c + 6 = 0 : c = 6

The solutions are

c = 3, c = - 1, c = 6

6 (x - 1)^{3} + 24 = - 24

6 (x + 5)^{5} = 64

x^{3} - 0.25 x = 0

9 x^{5} = 144 x^{3}

x^{3} - 4 x^{2} - x = - 4

What are the solutions to the equation (15-5c)(5c+5)(-c+6)=0 ?
The solutions to the equation (15-5c)(5c+5)(-c+6)=0 are c=3,c=-1,c=6
Find the zeros of (15-5c)(5c+5)(-c+6)=0
The zeros of (15-5c)(5c+5)(-c+6)=0 are c=3,c=-1,c=6