What are the solutions to the equation r^3-r^2-4r+4=0 ?

The solutions to the equation r^3-r^2-4r+4=0 are r=1,r=-2,r=2

Find the zeros of r^3-r^2-4r+4=0

The zeros of r^3-r^2-4r+4=0 are r=1,r=-2,r=2

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r^{3} - r^{2} - 4 r + 4 = 0

r = 1, r = - 2, r = 2

Solution steps

r^{3} - r^{2} - 4 r + 4 = 0

Factor

r^{3} - r^{2} - 4 r + 4 : (r - 1) (r + 2) (r - 2)

(r - 1) (r + 2) (r - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r - 1 = 0 or r + 2 = 0 or r - 2 = 0

Solve

r - 1 = 0 : r = 1

Solve

r + 2 = 0 : r = - 2

Solve

r - 2 = 0 : r = 2

The solutions are

r = 1, r = - 2, r = 2

2 x^{3} + x^{2} - 10 x = 0

x^{4} - 5 x^{2} + 5 = 0

2 = (1 + r)^{7}

x^{4} + 6 x^{2} - 27 = 0

x^{4} + 3 x^{3} - x^{2} - 3 x = 0

What are the solutions to the equation r^3-r^2-4r+4=0 ?
The solutions to the equation r^3-r^2-4r+4=0 are r=1,r=-2,r=2
Find the zeros of r^3-r^2-4r+4=0
The zeros of r^3-r^2-4r+4=0 are r=1,r=-2,r=2