What are the solutions to the equation 2x^3-7x^2+x+10=0 ?

The solutions to the equation 2x^3-7x^2+x+10=0 are x=-1,x=2,x= 5/2

Find the zeros of 2x^3-7x^2+x+10=0

The zeros of 2x^3-7x^2+x+10=0 are x=-1,x=2,x= 5/2

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2 x^{3} - 7 x^{2} + x + 10 = 0

x = - 1, x = 2, x = \frac{5}{2}

Decimal Notation

x = - 1, x = 2, x = 2.5

Solution steps

2 x^{3} - 7 x^{2} + x + 10 = 0

Factor

2 x^{3} - 7 x^{2} + x + 10 : (x + 1) (x - 2) (2 x - 5)

(x + 1) (x - 2) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 2 = 0 or 2 x - 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions are

x = - 1, x = 2, x = \frac{5}{2}

(x - 3)^{10} = 0

x = x (x - 2)^{2}

2 x^{3} - x^{2} - 15 x + 18 = 0

x^{4} - x^{2} + 3 = 0

x^{3} - 2 x^{2} + 5 x - 6 = 0

What are the solutions to the equation 2x^3-7x^2+x+10=0 ?
The solutions to the equation 2x^3-7x^2+x+10=0 are x=-1,x=2,x= 5/2
Find the zeros of 2x^3-7x^2+x+10=0
The zeros of 2x^3-7x^2+x+10=0 are x=-1,x=2,x= 5/2