What are the solutions to the equation 64x^3+24x^2-6x-1=0 ?

The solutions to the equation 64x^3+24x^2-6x-1=0 are x=-1/2 ,x=-1/8 ,x= 1/4

Find the zeros of 64x^3+24x^2-6x-1=0

The zeros of 64x^3+24x^2-6x-1=0 are x=-1/2 ,x=-1/8 ,x= 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

64 x^{3} + 24 x^{2} - 6 x - 1 = 0

x = - \frac{1}{2}, x = - \frac{1}{8}, x = \frac{1}{4}

Decimal Notation

x = - 0.5, x = - 0.125, x = 0.25

Solution steps

64 x^{3} + 24 x^{2} - 6 x - 1 = 0

Factor

64 x^{3} + 24 x^{2} - 6 x - 1 : (2 x + 1) (8 x + 1) (4 x - 1)

(2 x + 1) (8 x + 1) (4 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or 8 x + 1 = 0 or 4 x - 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

8 x + 1 = 0 : x = - \frac{1}{8}

Solve

4 x - 1 = 0 : x = \frac{1}{4}

The solutions are

x = - \frac{1}{2}, x = - \frac{1}{8}, x = \frac{1}{4}

4 x^{12} = 6

(x - 9) (x^{2} - 36) = 0

2 x^{3} - 6 x^{2} - 6 x + 18 = 0

9 x^{4} - 18 x^{2} + 5 = 0

m^{3} - 27 = (m - 3)

What are the solutions to the equation 64x^3+24x^2-6x-1=0 ?
The solutions to the equation 64x^3+24x^2-6x-1=0 are x=-1/2 ,x=-1/8 ,x= 1/4
Find the zeros of 64x^3+24x^2-6x-1=0
The zeros of 64x^3+24x^2-6x-1=0 are x=-1/2 ,x=-1/8 ,x= 1/4