What are the solutions to the equation y^3-2y^2+y=0 ?

The solutions to the equation y^3-2y^2+y=0 are y=0,y=1

Find the zeros of y^3-2y^2+y=0

The zeros of y^3-2y^2+y=0 are y=0,y=1

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y^{3} - 2 y^{2} + y = 0

y = 0, y = 1

Solution steps

y^{3} - 2 y^{2} + y = 0

Factor

y^{3} - 2 y^{2} + y : y (y - 1)^{2}

y (y - 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y - 1 = 0

Solve

y - 1 = 0 : y = 1

The solutions are

y = 0, y = 1

x^{4} - 12 x^{2} + 162 x - 12 = 0

x^{4} + 8 x^{3} + 16 x^{2} = 0

x^{4} + 130 x^{2} + 3969 = 0

81 x^{3} = x^{2}

3 m^{3} + 12 m^{2} - 135 m = 0

What are the solutions to the equation y^3-2y^2+y=0 ?
The solutions to the equation y^3-2y^2+y=0 are y=0,y=1
Find the zeros of y^3-2y^2+y=0
The zeros of y^3-2y^2+y=0 are y=0,y=1