What are the solutions to the equation (x^2-4)(x^2+8x+16)=0 ?

The solutions to the equation (x^2-4)(x^2+8x+16)=0 are x=-4,x=-2,x=2

Find the zeros of (x^2-4)(x^2+8x+16)=0

The zeros of (x^2-4)(x^2+8x+16)=0 are x=-4,x=-2,x=2

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(x^{2} - 4) (x^{2} + 8 x + 16) = 0

x = - 4, x = - 2, x = 2

Solution steps

(x^{2} - 4) (x^{2} + 8 x + 16) = 0

Factor

(x^{2} - 4) (x^{2} + 8 x + 16) : (x + 4)^{2} (x + 2) (x - 2)

(x + 4)^{2} (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 4, x = - 2, x = 2

x^{3} - 3 x^{2} - 2 x = 0

2 x^{3} + 8 x - 4 = 0

X^{4} - 3 X^{2} + 1 = 0

2 x^{3} - x^{2} + x - 1 = 2 x - 1

x^{3} - 25 = 1 0^{2}

What are the solutions to the equation (x^2-4)(x^2+8x+16)=0 ?
The solutions to the equation (x^2-4)(x^2+8x+16)=0 are x=-4,x=-2,x=2
Find the zeros of (x^2-4)(x^2+8x+16)=0
The zeros of (x^2-4)(x^2+8x+16)=0 are x=-4,x=-2,x=2