What are the solutions to the equation c^3-c^2+c-6=0 ?

The solutions to the equation c^3-c^2+c-6=0 are c=2,c=-1/2+i(sqrt(11))/2 ,c=-1/2-i(sqrt(11))/2

Find the zeros of c^3-c^2+c-6=0

The zeros of c^3-c^2+c-6=0 are c=2,c=-1/2+i(sqrt(11))/2 ,c=-1/2-i(sqrt(11))/2

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c^{3} - c^{2} + c - 6 = 0

c = 2, c = - \frac{1}{2} + i \frac{11}{2}, c = - \frac{1}{2} - i \frac{11}{2}

Solution steps

c^{3} - c^{2} + c - 6 = 0

Factor

c^{3} - c^{2} + c - 6 : (c - 2) (c^{2} + c + 3)

(c - 2) (c^{2} + c + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

c - 2 = 0 or c^{2} + c + 3 = 0

Solve

c - 2 = 0 : c = 2

Solve

c^{2} + c + 3 = 0 : c = - \frac{1}{2} + i \frac{11}{2}, c = - \frac{1}{2} - i \frac{11}{2}

The solutions are

c = 2, c = - \frac{1}{2} + i \frac{11}{2}, c = - \frac{1}{2} - i \frac{11}{2}

x, 25 x^{4} - 625 y - 500 = 0

2 x^{3} + 10 x^{2} + 12 x = 0

0 = 2 x^{3} + 3

y^{5} - 18 y^{4} + 69 y^{3} = 0

x^{3} - 9 x^{2} + 24 x - 8 = 0

What are the solutions to the equation c^3-c^2+c-6=0 ?
The solutions to the equation c^3-c^2+c-6=0 are c=2,c=-1/2+i(sqrt(11))/2 ,c=-1/2-i(sqrt(11))/2
Find the zeros of c^3-c^2+c-6=0
The zeros of c^3-c^2+c-6=0 are c=2,c=-1/2+i(sqrt(11))/2 ,c=-1/2-i(sqrt(11))/2