What are the solutions to the equation 2x^3=2 ?

The solutions to the equation 2x^3=2 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

Find the zeros of 2x^3=2

The zeros of 2x^3=2 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{3} = 2

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

Solution steps

2 x^{3} = 2

Divide both sides by

2

x^{3} = 1

For

x^{3} = f (a)

the solutions are

x = 1, x = \frac{- 1 + 3 i}{2}, x = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

x = 1, x = - \frac{1}{2} + \frac{3}{2} i, x = - \frac{1}{2} - \frac{3}{2} i

x^{3} + 2 x^{2} - 4 x - 2 = 0

x^{3} - 4 x^{2} + 7 x - 6 = 0

(x + 6)^{3} = 0

2 x^{3} + 4 x + 3 = 0

t^{4} - 625 = 0

What are the solutions to the equation 2x^3=2 ?
The solutions to the equation 2x^3=2 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i
Find the zeros of 2x^3=2
The zeros of 2x^3=2 are x=1,x=-1/2+(sqrt(3))/2 i,x=-1/2-(sqrt(3))/2 i