What are the solutions to the equation 3x^2+240=0 ?

The solutions to the equation 3x^2+240=0 are x=4sqrt(5)i,x=-4sqrt(5)i

Find the zeros of 3x^2+240=0

The zeros of 3x^2+240=0 are x=4sqrt(5)i,x=-4sqrt(5)i

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3 x^{2} + 240 = 0

x = 45 i, x = - 45 i

Solution steps

3 x^{2} + 240 = 0

Move

240

to the right side

3 x^{2} = - 240

Divide both sides by

3

x^{2} = - 80

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 80, x = - - 80

- 80 = 45 i

- - 80 = - 45 i

x = 45 i, x = - 45 i

\frac{- 4}{3 ^{2}}

3 e^{- 1}

∣ 2 p - 1 ∣ = ∣ 1 - 2 p ∣

(3 n)^{\frac{1}{2}}

x^{2} + 2 x - 3 < 0

What are the solutions to the equation 3x^2+240=0 ?
The solutions to the equation 3x^2+240=0 are x=4sqrt(5)i,x=-4sqrt(5)i
Find the zeros of 3x^2+240=0
The zeros of 3x^2+240=0 are x=4sqrt(5)i,x=-4sqrt(5)i