What are the solutions to the equation 16x^4+24x^2+9x=0 ?

The solutions to the equation 16x^4+24x^2+9x=0 are x=0,x\approx-0.34711…

Find the zeros of 16x^4+24x^2+9x=0

The zeros of 16x^4+24x^2+9x=0 are x=0,x\approx-0.34711…

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16 x^{4} + 24 x^{2} + 9 x = 0

x = 0, x \approx - 0.34711 \dots

Solution steps

16 x^{4} + 24 x^{2} + 9 x = 0

Factor

16 x^{4} + 24 x^{2} + 9 x : x (16 x^{3} + 24 x + 9)

x (16 x^{3} + 24 x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 16 x^{3} + 24 x + 9 = 0

Solve

16 x^{3} + 24 x + 9 = 0 : x \approx - 0.34711 \dots

The solutions are

x = 0, x \approx - 0.34711 \dots

- x^{3} + 11 x^{2} - 38 x + 44 = 0

3^{3} = 2^{3} (c^{3})

(4 x^{2} + 3 x - 10)^{2} = 9 x^{4}

35 x^{4} - 2 x^{2} - 1 = 0

x^{12} - 3 = 9

What are the solutions to the equation 16x^4+24x^2+9x=0 ?
The solutions to the equation 16x^4+24x^2+9x=0 are x=0,x\approx-0.34711…
Find the zeros of 16x^4+24x^2+9x=0
The zeros of 16x^4+24x^2+9x=0 are x=0,x\approx-0.34711…