What are the solutions to the equation x^3-5x^2+2x+14=x^2-3x+2 ?

The solutions to the equation x^3-5x^2+2x+14=x^2-3x+2 are x=-1,x=3,x=4

Find the zeros of x^3-5x^2+2x+14=x^2-3x+2

The zeros of x^3-5x^2+2x+14=x^2-3x+2 are x=-1,x=3,x=4

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x^{3} - 5 x^{2} + 2 x + 14 = x^{2} - 3 x + 2

x = - 1, x = 3, x = 4

Solution steps

x^{3} - 5 x^{2} + 2 x + 14 = x^{2} - 3 x + 2

Move

2

to the left side

x^{3} - 5 x^{2} + 2 x + 12 = x^{2} - 3 x

Move

3 x

to the left side

x^{3} - 5 x^{2} + 5 x + 12 = x^{2}

Move

x^{2}

to the left side

x^{3} - 6 x^{2} + 5 x + 12 = 0

Factor

x^{3} - 6 x^{2} + 5 x + 12 : (x + 1) (x - 3) (x - 4)

(x + 1) (x - 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 3 = 0 or x - 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

Solve

x - 4 = 0 : x = 4

The solutions are

x = - 1, x = 3, x = 4

- x^{3} + 2 x^{2} + 2 x + 1 = 0

(x^{2} + 3)^{2} = 18 - 2 x^{2}

9 x^{4} + 25 = 34 x^{2}

4 = \frac{1}{2} x^{3}

10 x^{4} - 13 x^{2} + 4 = 0

What are the solutions to the equation x^3-5x^2+2x+14=x^2-3x+2 ?
The solutions to the equation x^3-5x^2+2x+14=x^2-3x+2 are x=-1,x=3,x=4
Find the zeros of x^3-5x^2+2x+14=x^2-3x+2
The zeros of x^3-5x^2+2x+14=x^2-3x+2 are x=-1,x=3,x=4