What are the solutions to the equation (x+7)^3(x-2i)(x+2i)=0 ?

The solutions to the equation (x+7)^3(x-2i)(x+2i)=0 are x=-7,x=2i,x=-2i

Find the zeros of (x+7)^3(x-2i)(x+2i)=0

The zeros of (x+7)^3(x-2i)(x+2i)=0 are x=-7,x=2i,x=-2i

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(x + 7)^{3} (x - 2 i) (x + 2 i) = 0

x = - 7, x = 2 i, x = - 2 i

Solution steps

(x + 7)^{3} (x - 2 i) (x + 2 i) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 7 = 0 or x - 2 i = 0 or x + 2 i = 0

Solve

x + 7 = 0 : x = - 7

Solve

x - 2 i = 0 : x = 2 i

Solve

x + 2 i = 0 : x = - 2 i

The solutions are

x = - 7, x = 2 i, x = - 2 i

4 x^{3} + 7 x^{2} - 12 x - 21 = 0

x^{4} - 5 x^{2} + 6 x - 4 = 0

5 x^{4} = 80

n^{3} - 3 n = 40

2 x^{3} = - 3 x^{2} + 2 x

What are the solutions to the equation (x+7)^3(x-2i)(x+2i)=0 ?
The solutions to the equation (x+7)^3(x-2i)(x+2i)=0 are x=-7,x=2i,x=-2i
Find the zeros of (x+7)^3(x-2i)(x+2i)=0
The zeros of (x+7)^3(x-2i)(x+2i)=0 are x=-7,x=2i,x=-2i