What are the solutions to the equation n^3=125 ?

The solutions to the equation n^3=125 are n=5,n=-5/2+(5sqrt(3))/2 i,n=-5/2-(5sqrt(3))/2 i

Find the zeros of n^3=125

The zeros of n^3=125 are n=5,n=-5/2+(5sqrt(3))/2 i,n=-5/2-(5sqrt(3))/2 i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{3} = 125

n = 5, n = - \frac{5}{2} + \frac{5 3}{2} i, n = - \frac{5}{2} - \frac{5 3}{2} i

Solution steps

n^{3} = 125

For

x^{3} = f (a)

the solutions are

Simplify

n = 5, n = - \frac{5}{2} + \frac{5 3}{2} i, n = - \frac{5}{2} - \frac{5 3}{2} i

(x + 2) (x - 3) (x + 1) (x + 6) = - 36

x + x^{2} - x^{3} - x^{4} = 0

4 x^{5} + 5 x^{2} - 3 x = 0

u^{4} = - 8 i

16 x^{4} + 8 x^{2} - 3 = 0

What are the solutions to the equation n^3=125 ?
The solutions to the equation n^3=125 are n=5,n=-5/2+(5sqrt(3))/2 i,n=-5/2-(5sqrt(3))/2 i
Find the zeros of n^3=125
The zeros of n^3=125 are n=5,n=-5/2+(5sqrt(3))/2 i,n=-5/2-(5sqrt(3))/2 i