What are the solutions to the equation x(x^2-5x+14)=0 ?

The solutions to the equation x(x^2-5x+14)=0 are x=0,x= 5/2+i(sqrt(31))/2 ,x= 5/2-i(sqrt(31))/2

Find the zeros of x(x^2-5x+14)=0

The zeros of x(x^2-5x+14)=0 are x=0,x= 5/2+i(sqrt(31))/2 ,x= 5/2-i(sqrt(31))/2

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x (x^{2} - 5 x + 14) = 0

x = 0, x = \frac{5}{2} + i \frac{31}{2}, x = \frac{5}{2} - i \frac{31}{2}

Solution steps

x (x^{2} - 5 x + 14) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} - 5 x + 14 = 0

Solve

x^{2} - 5 x + 14 = 0 : x = \frac{5}{2} + i \frac{31}{2}, x = \frac{5}{2} - i \frac{31}{2}

The solutions are

x = 0, x = \frac{5}{2} + i \frac{31}{2}, x = \frac{5}{2} - i \frac{31}{2}

x^{3} - 3 x^{2} - 2 x - 8 = 0

x^{4} - 10 x^{2} - x + 20 = 0

10 = 0.2 x^{3} + 0.1 x^{5}

z, x = z^{3}

4 x^{3} + 5 x^{2} - 60 x - 75 = 0

What are the solutions to the equation x(x^2-5x+14)=0 ?
The solutions to the equation x(x^2-5x+14)=0 are x=0,x= 5/2+i(sqrt(31))/2 ,x= 5/2-i(sqrt(31))/2
Find the zeros of x(x^2-5x+14)=0
The zeros of x(x^2-5x+14)=0 are x=0,x= 5/2+i(sqrt(31))/2 ,x= 5/2-i(sqrt(31))/2