What are the solutions to the equation x^3-3x^2-3x+9=0 ?

The solutions to the equation x^3-3x^2-3x+9=0 are x=3,x=-sqrt(3),x=sqrt(3)

Find the zeros of x^3-3x^2-3x+9=0

The zeros of x^3-3x^2-3x+9=0 are x=3,x=-sqrt(3),x=sqrt(3)

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x^{3} - 3 x^{2} - 3 x + 9 = 0

x = 3, x = - 3, x = 3

Decimal Notation

x = 3, x = - 1.73205 \dots, x = 1.73205 \dots

Solution steps

x^{3} - 3 x^{2} - 3 x + 9 = 0

Factor

x^{3} - 3 x^{2} - 3 x + 9 : (x - 3) (x + 3) (x - 3)

(x - 3) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = 3, x = - 3, x = 3

x, 7 x^{6} = y^{2} x

x, x^{4} - 4 x^{2} - y = 0

- 5 s s^{2} - 16 + 8 s + 4 = 1 s - 4

x^{3} - 6 x^{2} + 3 x + 3 = 0

0 = 4 x^{3} - 6 x^{2}

What are the solutions to the equation x^3-3x^2-3x+9=0 ?
The solutions to the equation x^3-3x^2-3x+9=0 are x=3,x=-sqrt(3),x=sqrt(3)
Find the zeros of x^3-3x^2-3x+9=0
The zeros of x^3-3x^2-3x+9=0 are x=3,x=-sqrt(3),x=sqrt(3)