What are the solutions to the equation 8q-14q^2-4q^3=0 ?

The solutions to the equation 8q-14q^2-4q^3=0 are q=0,q= 1/2 ,q=-4

Find the zeros of 8q-14q^2-4q^3=0

The zeros of 8q-14q^2-4q^3=0 are q=0,q= 1/2 ,q=-4

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8 q - 14 q^{2} - 4 q^{3} = 0

q = 0, q = \frac{1}{2}, q = - 4

Decimal Notation

q = 0, q = 0.5, q = - 4

Solution steps

8 q - 14 q^{2} - 4 q^{3} = 0

Factor

8 q - 14 q^{2} - 4 q^{3} : - 2 q (2 q - 1) (q + 4)

- 2 q (2 q - 1) (q + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

q = 0 or 2 q - 1 = 0 or q + 4 = 0

Solve

2 q - 1 = 0 : q = \frac{1}{2}

Solve

q + 4 = 0 : q = - 4

The solutions are

q = 0, q = \frac{1}{2}, q = - 4

1 + x^{3} = 0

x^{3} - 3 x = 4

- 106 = - 8 c^{3} - 2

0 = x^{4} + x^{2} + 1

r, A = 4 r π r^{2}

What are the solutions to the equation 8q-14q^2-4q^3=0 ?
The solutions to the equation 8q-14q^2-4q^3=0 are q=0,q= 1/2 ,q=-4
Find the zeros of 8q-14q^2-4q^3=0
The zeros of 8q-14q^2-4q^3=0 are q=0,q= 1/2 ,q=-4